3[(x^2+4)]=15

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Solution for 3[(x^2+4)]=15 equation:


Simplifying
3[x2 + 4] = 15

Reorder the terms:
3[4 + x2] = 15
[4 * 3 + x2 * 3] = 15
[12 + 3x2] = 15

Solving
12 + 3x2 = 15

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + 3x2 = 15 + -12

Combine like terms: 12 + -12 = 0
0 + 3x2 = 15 + -12
3x2 = 15 + -12

Combine like terms: 15 + -12 = 3
3x2 = 3

Divide each side by '3'.
x2 = 1

Simplifying
x2 = 1

Take the square root of each side:
x = {-1, 1}

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